50x^2-47x-3=0

Solution for 50x^2-47x-3=0 equation:

50x^2-47x-3=0

a = 50; b = -47; c = -3;
Δ = b2-4ac
Δ = -472-4·50·(-3)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-53}{2*50}=\frac{-6}{100}
=-3/50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+53}{2*50}=\frac{100}{100}
=1
$